An empty bus starts its daily route. Along the way it makes several stops. At each stop, some passengers board the bus and some passengers exit the bus.
The table shows how many passengers get on and get off the bus at each stop.
Stop Number | Number Boarding | Number Exiting |
---|---|---|
\(1\) | \(23\) | \(0\) |
\(2\) | \(17\) | \(12\) |
\(3\) | \(13\) | \(3\) |
\(4\) | \(1\) | \(9\) |
\(5\) | \(2\) | \(8\) |
How many passengers board the bus in total?
The bus has seats for \(30\) passengers. Once all the seats are full, passengers must stand. Between the 3rd and 4th stops, are there enough seats for all the passengers? If not, how many passengers must stand?
The bus gets a flat tire at the 6th stop so all the passengers need to exit. How many passengers get off the bus at the 6th stop?
The total number of passengers who board the bus is: \(23 + 17 + 13 + 1 + 2 = 56\).
The table summarizes the number of passengers on the bus after each stop.
Stop Number | Number Boarding | Number Exiting | Total Passengers on the Bus |
---|---|---|---|
\(1\) | \(23\) | \(0\) | \(23\) |
\(2\) | \(17\) | \(12\) | \(23 + 17 - 12 = 28\) |
\(3\) | \(13\) | \(3\) | \(28 + 13 - 3 = 38\) |
\(4\) | \(1\) | \(9\) | \(38 + 1 - 9 = 30\) |
\(5\) | \(2\) | \(8\) | \(30 + 2 - 8 = 24\) |
Thus, between the 3rd and 4th stops, there are \(38\) passengers on the bus. Since there are only \(30\) seats, there are not enough seats for all the passengers. The number of passengers who must stand is \(38 - 30 = 8\).
From the table in (b), we know that \(24\) passengers are on the bus when it arrives at the 6th stop. They would all need to exit. Thus, \(24\) passengers get off the bus at the 6th stop.