Thursday, April 4, 2024
(in North America and South America)
Friday, April 5, 2024
(outside of North American and South America)
©2024 University of Waterloo
The 5th term is obtained by adding
Solution 1:
The 6th term is obtained by adding
Solution 2:
The 4th term is
The
In general, the
Therefore, the 20th term is
Solution 1:
Since each new term is obtained by adding
(We note that
Solution 2:
From part (c), the
We want the smallest term that is greater than
Solving this inequality, we get
At Store 2,
That is, Ella dropped off an equal number of red and blue shirts at
Store 2.
All 200 blue shirts were dropped off at Store 2, and thus
At Store 1, Ella dropped off
Ella dropped off the remaining
Ella dropped off no blue shirts at Store 1, and so she dropped
off all
On Wednesday, Ella dropped off
Of all the shirts dropped off on Wednesday,
In Figure 2, each of the smaller pieces has the same length of
crust.
Thus, we must determine the length of
The area of square
Since
The smaller piece
Solving, we get
Alternately,
In Figure 3, each of the
Since the slice of bread has crusts on
Thus the length of crust for each of the
Since
The area of square
Consider a point
Since
The area of
Since
Each of the
The area of
Since
Since each player has
If Alice spins a
If Alice spins a
If Alice spins an
We summarize these results in the table below, using an A to indicate
that Alice wins and a B where Binh wins.
Alice's Spin | ||||
---|---|---|---|---|
Binh's Spin | A | A | A | |
B | A | A | ||
B | B | A |
We see that Alice wins
Carole’s spinner is
Since each player has
Thus, Darsh’s probability of winning is greater than Carole’s
probability of winning if the integer he spins is greater than Carole’s
for at least
If Carole spins a
When Carole spins a
If Carole spins a
There are similarly
To this point, Darsh wins
This tells us that the probability of Darsh winning is determined by
comparing
Specifically, if at least two of Darsh’s integers are greater than
Why is this true? When Carole spins a
To determine the number of different spinners for which at least two of
Darsh’s integers are greater than
Case 1: All three of Darsh’s integers are greater than
In this case, Darsh wins
Darsh's Spin | ||||
---|---|---|---|---|
Carole's Spin | D | D | D | |
D | D | D | ||
C | C | C |
Case 2: Two of Darsh’s integers are greater than
In this case, Darsh wins
Darsh's Spin | ||||
---|---|---|---|---|
Carole's Spin | D | D | D | |
C | D | D | ||
C | C | C |
Therefore, Darsh can make
We begin by determining the value of
We summarize these results in the table below, using an F to indicate
that Fynn wins and an E where Erin wins.
Fynn's Spin | ||||
---|---|---|---|---|
Erin's Spin | E | F | F | |
E | F | F | ||
E | E | F |
We see that Fynn wins
In the question, we are given that
This means that Erin wins exactly
We begin by considering the game in which Erin plays Gina.
Erin’s spinner is
For example, if Erin spins
Conversely, if Erin spins
We note that if a player’s spinner is {
There are three different ways that Erin can win exactly
These are:
Erin’s largest integer wins exactly
Erin’s largest integer wins exactly
Erin’s largest two integers each win exactly
We will refer to the first of these bullets as the
We note that in each case, the sum of the number of winning outcomes is
If the result in the game between Erin and Gina is
Recalling that Gina’s spinner is {
Thus, if Gina makes her spinner with
If the result is
Thus, if Gina makes her spinner with
Finally, if Erin beats Gina with a
We summarize these results in the table below.
Case | Result | Integer Ordering | Possible |
Possible |
Possible |
---|---|---|---|---|---|
1 | |||||
2 | |||||
3 |
(Note that in Case 2, the values of
We also require Gina’s spinner to be made so that the probability that
Gina beats Fynn is
In the game between Gina and Fynn, we use the same process and notation
as was used in the game between Erin and Gina.
In addition, we see from the table above that
In the table below, we exclude all other possible values of
Case | Result | Integer Ordering | Possible |
Possible |
Possible |
---|---|---|---|---|---|
4 | |||||
5 | |||||
6 |
(Note that in Cases 5 and 6, the values of
To make a spinner for which Erin beats Gina and Gina beats Fynn, each
with probability
We begin by determining if there are values for
To satisfy Case 1,
Next, we determine if there are values for
To satisfy Case 2,
If
Recalling that
For each of these
Finally, we determine if there are values for
To satisfy Case 3,
If
Since there are
Recognizing that the